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Proof step 1 from proof abs-02 (conclusion)

j ≠ 0 ⊦ abs(abs(i) / j) = abs(i / j)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: abs: j ≠ 0 ⊦ abs(i / j) = abs(i) / abs(j);%abs-01: ⊦ abs(abs(i)) = abs(i); from specification int-abs