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Proof step 10 from proof abs (previous step)

¬ i < 0 ⊦ abs(i / j) = i / abs(j), j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
0 ≤ i ⊦ abs(i / j) = i / abs(j), j = 0

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs