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Proof step 18 from proof add-div-mult (previous step)

j0 + i2 * j + j1 = j * i2 + j0 + j1, j1 < j, j0 < j, 0 < j, 0 ≤ j0, 0 ≤ i1, 0 ≤ j1, 0 ≤ i2, 0 ≤ j0 + i2 * j + j1, (j0 + j1) / j = 1 ∨ (j0 + j1) / j = 0 ⊦ i2 + (j0 + j1) / j = (j0 + i2 * j + j1) / j

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

Additional information