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Proof step 9 from proof div-add-nosucc (previous step)

j0 * j + j = i0 + 1, i0 / j = (j - 1) / j + j0, 0 ≤ j0, 1 < j, 0 < j ⊦ i0 / j = j0, j = 0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 10:
j = i1 + 1, j0 * j + j = i0 + 1, i0 / j = i1 / j + j0, 0 ≤ j0, 1 < j, 0 < j ⊦ i0 / j = j0, j = 0

Rule argument

spec: int-abs inst: name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [j, 1, i] flags:

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: j, 1, i