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Proof step 10 from proof div-add1-negpos-neg-01 (previous step)

i1 * j + i2 * j + j0 = i0 * j + j1 ∧ j1 ≤ 0 ∧ abs(j1) < j ∧ i0 ≤ 0, i1 * j < j0, i1 * j + i2 * j < j, i1 * j + i2 * j < j0, (i1 * j + i2 * j) + 1 < j0, 2 + i1 < j, i1 < j0, 0 ≤ i2, 0 < j, 1 < j, 1 + i1 * j + i2 * j + j0 < j, j + i1 * j ≤ 0, i1 < 0, i1 < j, j0 < j, 0 < j0, i1 * j + i2 * j < ~1, i1 * j + i2 * j + j0 < j, i1 * j + i2 * j + j0 < 0, 0 ≤ i2 * j + j0, j + i1 * j < j0, i1 + 1 < j0, i1 * j + i2 * j < 0, 2 + i1 * j + i2 * j < j ⊦ j0 = 0, j = 1, i0 = i1 + i2 + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: lst-04: ⊦ i + j < i0 ∧ j0 < j → i + j0 < i0; from specification int-basic2%zero-gels-04: ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; from specification int-abs%zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%lst-03: ⊦ i + j < i0 ∧ ¬ j < j0 → i + j0 < i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%succ-01: ⊦ i +1 = i + 1; from specification int-basic2%forward-lele: ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward) from specification int-abs%forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs%trans: ⊦ i < j ∧ j < j0 → i < j0; (forward) from specification int-basic1%lf-01: ⊦ i < j ∧ j < i0 → i +1 < i0; (forward) from specification int-basic1