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Proof step 13 from proof div-add1-negpos-neg-01 (previous step)

i1 * j + i2 * j + j0 = i0 * j + j1, (i0 * j + j1) + 1 < j0, abs(j1) < j, i1 * j < j0, i1 * j + i2 * j < j, i1 * j + i2 * j < j0, (i1 * j + i2 * j) + 1 < j0, 2 + i1 < j, i1 < j0, 0 ≤ i2, 0 < j, 1 < j, j + i1 * j ≤ 0, i1 < 0, i1 < j, j0 < j, 0 < j0, i1 * j + i2 * j < ~1, 0 ≤ i2 * j + j0, j + i1 * j < j0, i1 + 1 < j0, i1 * j + i2 * j < 0, 2 + i1 * j + i2 * j < j, j1 ≤ 0, j1 < j, j1 < j0, i0 ≤ 0, i0 < j, i0 < j0, i0 * j + j1 < 0, i0 * j + j1 < j, i0 * j + j1 < j0, 2 + i0 * j + j1 < j, j1 + 1 < j, i0 + 1 < j ⊦ (i2 + i1) * j + (j0 - j1) = i0 * j + 0 ∧ 0 ≤ j0 - j1 ∧ j0 - j1 < j ∧ 0 ≤ 0, j0 = 0, j = 1, i0 = i1 + i2 + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs%sub-ls: ⊦ i - j < i0 ↔ i < j + i0; from specification int-abs%sub-le-01: ⊦ i ≤ j - i0 ↔ i + i0 ≤ j; from specification int-abs%sub-eq: ⊦ i - j = i0 ↔ i = i0 + j; from specification int-abs%add-zero-rev: ⊦ 0 + i = i; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%sub-add-01: ⊦ i + (j - i0) = i + j - i0; from specification int-abs