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Proof step 6 from proof div-am-rew (previous step)

i + i0 * (i2 * j + j0) = (i + i0 * j0) + i0 * i2 * j, j0 < j, 0 ≤ i, 0 ≤ i0, 0 < j, 0 ≤ j0, 0 ≤ i2 ⊦ (i + i0 * (i2 * j + j0)) / j = (i + i0 * j0) / j + i0 * i2

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

Additional information