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Proof step 13 from proof div-div-pred-01 (previous step)

i1 * 4 + j1 < 0, ((i1 * 4 + j1) + 3) * 2 + j0 < 0, i1 * 4 + j1 ≤ ~3, j0 ≤ 0, ((i1 * 4 + j1) + 3) * 2 + j0 < ~1, j1 ≤ 0, i1 ≤ 0, abs(j1) < 4, abs(j0) < 2 ⊦ i1 = (j0 + ((i1 * 4 + j1) + 3) * 2 - 6) / 8

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

spec: int-abs inst: name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [j0 + ((i1 * 4 + j1) + 3) * 2, 6, i] flags:

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: j0 + ((i1 * 4 + j1) + 3) * 2, 6, i