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Proof step 29 from proof div-div-pred-01 (previous step)

¬((8 * i1) % 8 = 0 ∧ 8 * i1 < 0 ∧ j0 + j1 * 2 < 0 ∧ 0 < 8), j0 ≤ 0, i1 * 4 + j1 ≤ ~3, i1 * 4 + j1 < 0, abs(j0) < 2, abs(j1) < 4, i1 ≤ 0, j1 ≤ 0, 8 * i1 + j0 + j1 * 2 < ~7, 8 * i1 + j0 + j1 * 2 < 0 ⊦ i1 = (8 * i1 + j0 + j1 * 2) / 8

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
j0 ≤ 0, i1 * 4 + j1 ≤ ~3, i1 * 4 + j1 < 0, abs(j0) < 2, abs(j1) < 4, i1 ≤ 0, j1 ≤ 0, 8 * i1 + j0 + j1 * 2 < ~7, 8 * i1 + j0 + j1 * 2 < 0 ⊦ i1 = (8 * i1 + j0 + j1 * 2) / 8, i1 < 0 ∧ j0 + j1 * 2 < 0

Rule argument

Additional information

Used simplifier rules: mod-zero-num: i0 % j = 0, j ≠ 0 ⊦ (i * (* i0)) % (* j) = 0;%zero-ls: ⊦ 0 < i → (i * j < 0 ↔ j < 0); from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult