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Proof step 34 from proof div-div-pred-01 (previous step)

¬(j0 < 0 ∧ j1 * 2 < 0), abs(j1) < 4, abs(j0) < 2, i1 * 4 + j1 < 0, i1 * 4 + j1 ≤ ~3, j0 ≤ 0, 8 * i1 + j0 + j1 * 2 < 0, 8 * i1 + j0 + j1 * 2 < ~7, j1 ≤ 0, 0 ≤ j0 + j1 * 2, i1 < 0, i1 * 4 < j1 + j0 ⊦ i1 = (8 * i1 + j0 + j1 * 2) / 8, i1 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 35:
abs(j1) < 4, abs(j0) < 2, i1 * 4 + j1 < 0, i1 * 4 + j1 ≤ ~3, j0 ≤ 0, 8 * i1 + j0 + j1 * 2 < 0, 8 * i1 + j0 + j1 * 2 < ~7, j1 ≤ 0, 0 ≤ j0 + j1 * 2, i1 < 0, i1 * 4 < j1 + j0 ⊦ i1 = (8 * i1 + j0 + j1 * 2) / 8, i1 = 0, j0 < 0 ∧ j1 < 0

Rule argument

Additional information

Used simplifier rules: commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%zero-ls: ⊦ 0 < i → (i * j < 0 ↔ j < 0); from specification int-mult