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Proof step 4 from proof div-div-pred (previous step)

i0 < ~1, i0 < 0 ⊦ (i0 / 2 - 1) / 2 = (i0 - 2) / 4

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 5:
i0 = i1 + 2, i0 < ~1, i0 < 0 ⊦ (i0 / 2 - 1) / 2 = i1 / 4

Rule argument

spec: int-abs inst: name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [i0, 2, i] flags:

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: i0, 2, i