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Proof step 6 from proof div-div-pred (previous step)

i1 < ~3, i1 < 0 ⊦ ((i1 + 2) / 2 - 1) / 2 = i1 / 4

User applied rule insert elim lemma

And obtained the following new goals

Proof step 7:
(i1 + 2) / 2 = i0 + 1, i1 < ~3, i1 < 0 ⊦ i0 / 2 = i1 / 4

Rule argument

spec: int-abs inst: name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [(i1 + 2) / 2, 1, i] flags: []

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: (i1 + 2) / 2, 1, i