[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 17 from proof div-div (previous step)

(i / abs(j)) / abs(j0) + ~ i / (abs(j) * abs(j0)) = 0, i < 0 ⊦ (i / j) / j0 = i / (j * j0), j0 = 0, j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 18:
⊦ i < 0 → abs(i) = ~ i
Proof step 19:
¬ j < 0, (i / abs(j)) / abs(j0) + ~ i / (abs(j) * abs(j0)) = 0, i < 0 ⊦ (i / j) / j0 = i / (j * j0), j0 = 0, j = 0
Proof step 24:
j < 0, (i / ~ j) / abs(j0) + ~ i / (~ j * abs(j0)) = 0, i < 0 ⊦ (i / j) / j0 = i / (j * j0), j0 = 0, j = 0

Rule argument

spec: int-abs inst: name: abs-08 seq: ⊦ i < 0 → abs(i) = ~ i subst: [i] → [j] flags: rewrite

Additional information

Used terms: j