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Proof step 4 from proof div-div (previous step)

0 ≤ abs(i) ∧ 0 < abs(j) ∧ 0 < abs(j0) → (abs(i) / abs(j)) / abs(j0) = abs(i) / (abs(j) * abs(j0)) ⊦ (i / j) / j0 = i / (j * j0), j0 = 0, j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
(abs(i) / abs(j)) / abs(j0) = abs(i) / (abs(j) * abs(j0)) ⊦ (i / j) / j0 = i / (j * j0), j0 = 0, j = 0

Rule argument

Additional information

Used simplifier rules: abs-06: ⊦ 0 < abs(i) ↔ i ≠ 0; from specification int-abs%abs-03: ⊦ 0 ≤ abs(i); from specification int-abs