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Proof step 7 from proof div-div (previous step)

¬ i < 0, (abs(i) / abs(j)) / abs(j0) = abs(i) / (abs(j) * abs(j0)) ⊦ (i / j) / j0 = i / (j * j0), j0 = 0, j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
(i / abs(j)) / abs(j0) = i / (abs(j) * abs(j0)), 0 ≤ i ⊦ (i / j) / j0 = i / (j * j0), j0 = 0, j = 0

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs%Abs-pos: ⊦ ¬ j < 0 → abs(j) = j; from specification int-abs