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Proof step 11 from proof div-eq-same-01 (previous step)

0 < j, i / j = i ⊦ j = 0, i = 0, j = 1, j < 0 ∧ i < 0, 0 < j ∧ 0 < i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
i / j = i, i < j, i < 0, 0 < j, i + 1 < j ⊦ j = 0, j = 1

Rule argument

Additional information

Used simplifier rules: succ-01: ⊦ i +1 = i + 1; from specification int-basic2%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%trans: ⊦ i < j ∧ j < j0 → i < j0; (forward) from specification int-basic1%lf-01: ⊦ i < j ∧ j < i0 → i +1 < i0; (forward) from specification int-basic1%lst-01: ⊦ ¬ i < j → (i ≠ j ↔ j < i); from specification int-basic1%ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1