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Proof step 14 from proof div-eq-same (previous step)

j * i / j = i ⊦ 0 = j, i % j = 0, 0 < j ∧ 0 ≤ i, j < 0 ∧ 0 ≤ i, 0 < j ∧ i < 0, j < 0 ∧ i < 0

User applied rule case distinction

And closed the goal!

Rule argument

pos: right 4

Additional information

Used simplifier rules: lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs%zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%lst-01: ⊦ ¬ i < j → (i ≠ j ↔ j < i); from specification int-basic1%ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1