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Proof step 28 from proof div-eq-zero-01 (previous step)

i / j = 0, j < 0, 0 ≤ i ⊦ i + j < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 29:
i / j = 0, 0 ≤ i, j < 0, 0 ≤ i + j ⊦

Rule argument

Additional information

Used simplifier rules: zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs%lf-02: ⊦ i < j ∧ j = i0 → i < i0; (forward) from specification int-basic1%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs