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Proof step 33 from proof div-eq-zero-01 (previous step)

i + j < 0, j < 0, 0 ≤ i ⊦ i / j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 34:
i + j < 0, 0 ≤ i, j < 0 ⊦ i / j = 0

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%ls: ⊦ i + j < j ↔ i < 0; from specification int-basic2%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs