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Proof step 3 from proof div-eq-zero (previous step)

i / j = 0, 0 < i, 0 < j ⊦ i < j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
i / j = 0, 0 < i, 0 < j, j ≤ i ⊦

Rule argument

Additional information

Used simplifier rules: lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs