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Proof step 2 from proof div-le-modzero-01 (previous step)

i % j = 0, 0 ≤ i, 0 < j ⊦ i / j ≤ i0 ↔ ¬ i0 * j < i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i ≤ j ↔ ¬ j < i
Proof step 4:
i % j = 0, 0 ≤ i, 0 < j ⊦ ¬ i0 < i / j ↔ ¬ i0 * j < i

Rule argument

spec: int-abs inst: name: le-def seq: ⊦ i ≤ j ↔ ¬ j < i subst: [j, i] → [i0, i / j] flags: rewrite

Additional information

Used terms: i0, i / j