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Proof step 6 from proof div-le-pos (previous step)

i < j, i < 0, i0 / j < i / j, 0 < j, i0 / j < j0, i ≤ i0, j0 ≤ i / j, i + 1 < j ⊦ j < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
i < j, i < 0, i0 / j < i / j, 0 < j, i0 / j < j0, i ≤ i0, j0 ≤ i / j, i + 1 < j ⊦

Rule argument

Additional information

Used simplifier rules: ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1