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Proof step 3 from proof div-lezero (previous step)

i / j ≤ 0, 0 < j ⊦ i < j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
0 < i, i / j < j, i / j ≤ 0, j ≤ i, 0 < j, i / j < i ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs%forward-le: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward) from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs