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Proof step 7 from proof div-lezero (previous step)

i < j, 0 < j, 0 < i / j ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 8:
i < 0, i < j, 0 < j, 0 < i / j ⊦

Rule argument

fma: i < 0

Additional information

Used simplifier rules: div-zero-05: ⊦ i < j ∧ 0 < j ∧ 0 ≤ i → i / j = 0;%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs Used formulas: i < 0