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Proof step 1 from proof div-ls-02 (conclusion)

0 < j0, 0 ≤ i, i ≤ j, i / j0 ≠ j / j0 ⊦ i / j0 < j / j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i ≤ j, j / j0 < i / j0, 0 < j0, 0 ≤ i, 0 ≤ j ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1%lst-01: ⊦ ¬ i < j → (i ≠ j ↔ j < i); from specification int-basic1