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Proof step 2 from proof div-ls-mone (previous step)

0 < j ⊦ i / j < ~1 ↔ i + 2 * j ≤ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
0 < j ⊦ i / j < ~1 ↔ i + 2 * j ≤ 0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs