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Proof step 14 from proof div-ls-same (previous step)

i0 ≤ i0 * j + j0, i0 * j + j0 < j, i0 < j, j0 < j, j0 ≤ 0, (i0 * j + j0) + 1 < j, abs(j0) < j, i0 < 0, 1 < j, 0 < j, i0 + 1 < j ⊦ j = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 15:
⊦ ¬ i < j ↔ j ≤ i
Proof step 16:
i0 ≤ i0 * j + j0, i0 * j + j0 < j, i0 < j, j0 < j, j0 ≤ 0, (i0 * j + j0) + 1 < j, abs(j0) < j, i0 < 0, ¬ j ≤ 1, 0 < j, i0 + 1 < j ⊦ j = 1

Rule argument

spec: int-abs inst: name: lels seq: ⊦ ¬ i < j ↔ j ≤ i subst: [j, i] → [j, 1] flags: rewrite

Additional information

Used terms: j, 1