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Proof step 7 from proof div-minus-onediff-01 (previous step)

i0 = (j0 - 1) * j + 1, j0 * j + 1 = i0 + j, i0 < j, i0 < 0, 0 < j, j + j0 * j ≤ 0, j0 < 0, j0 < j, j0 + 1 < j, i0 + 1 < j ⊦ j = 0, j = 1, i0 / j = j0

User applied rule insert equation

And obtained the following new goals

Proof step 8:
j0 * j + 1 = ((j0 - 1) * j + 1) + j, (j0 - 1) * j + 1 < j, (j0 - 1) * j + 1 < 0, 0 < j, j + j0 * j ≤ 0, j0 < 0, j0 < j, j0 + 1 < j, ((j0 - 1) * j + 1) + 1 < j ⊦ j = 0, j = 1, ((j0 - 1) * j + 1) / j = j0

Rule argument

pos: left 1 flags: discard

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