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Proof step 6 from proof div-minus-onediff (previous step)

(i0 * j + j0) + 1 - j = j * (i0 - 1) + j0 + 1, j0 < j, j0 < 0, i0 * j + j0 < j, i0 * j + j0 < 0, i0 < j + j0, i0 < j, i0 ≤ 0, (i0 * j + j0) + 1 < j, 0 < j + j0, j0 + 1 < j, 1 < j, 0 < j ⊦ j0 = 0, i0 = ((i0 * j + j0) + 1 - j) / j + 1

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

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