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Proof step 2 from proof div-minus255-256-01 (previous step)

i % 256 = 0, i ≤ ~256, i < 0 ⊦ (i - 255) / 256 = i / 256

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i % j = 0 ∧ j0 = j - 1 ∧ i < 0 ∧ 0 < j → (i - j0) / j = i / j

Rule argument

spec: int-div inst: name: div-minus-onediff-01 seq: ⊦ i % j = 0 ∧ j0 = j - 1 ∧ i < 0 ∧ 0 < j → (i - j0) / j = i / j subst: [j, j0, i] → [256, 255, i] flags: rewrite, current

Additional information

Used simplifier rules: zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs Used terms: 256, 255, i