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Proof step 32 from proof div-mult-01 (
previous step
)
0 < i0, 0 < j, 0 ≤ i ⊦ (i * i0) / (j * i0) = i / j
User applied rule insert lemma
And obtained the following new goals
Proof step 33
:
0 < j, 0 < i0, 0 ≤ i ⊦ (i * i0) / (j * i0) = i / j
Rule argument
spec: int-div inst: name: div-mult-02 seq: 0 < j, 0 < i0, 0 ≤ i ⊦ (i * i0) / (j * i0) = i / j subst: [j, i0, i] → [j, i0, i] flags: current, []
Additional information
Used terms: j, i0, i