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Proof step 1 from proof div-mult-nls-est-01 (conclusion)

0 < i, 0 ≤ j ⊦ ¬ i0 ≤ j / i → ¬ i * i0 < j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i * i0 < j, j / i < i0, 0 < i, 0 ≤ j ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs