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Proof step 6 from proof div-mult-three-nls (
previous step
)
i0 * 3 + j0 < j * 3 + j0, j * j * j = i0 * 3 + j0, i0 < j, 2 ≤ j, 0 < j, j0 < 3, 0 ≤ j, 0 ≤ j0, 0 ≤ i0 ⊦
User applied rule insert equation
And obtained the following new goals
Proof step 7
:
j * j * j < j * 3 + j0, i0 < j, 2 ≤ j, 0 < j, j0 < 3, 0 ≤ j, 0 ≤ j0, 0 ≤ i0 ⊦
Rule argument
pos: left 2 flags: rotate, discard
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