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Proof step 11 from proof div-mult-two-nls-01 (previous step)

2 * i0 * j = (2 * i0) * j, 2 * i0 * j + 2 * j0 = i1 * j + j1, j1 < j, j0 < j, 1 + 2 * i0 < i1, 0 < j, 0 ≤ j0, 0 ≤ i0, 0 ≤ j1, 0 ≤ i1 ⊦

User applied rule insert equation

And obtained the following new goals

Proof step 12:
(2 * i0) * j + 2 * j0 = i1 * j + j1, j1 < j, j0 < j, 1 + 2 * i0 < i1, 0 < j, 0 ≤ j0, 0 ≤ i0, 0 ≤ j1, 0 ≤ i1 ⊦

Rule argument

pos: left 1 flags: discard

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