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Proof step 2 from proof div-nearer-zero (previous step)

abs(i) < abs(i) / abs(j) * abs(j) ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ j < 0 → abs(j) = 0 - j
Proof step 4:
¬ i < 0, abs(i) < abs(i) / abs(j) * abs(j) ⊦ j = 0
Proof step 13:
i < 0, 0 - i < (0 - i) / abs(j) * abs(j) ⊦ j = 0

Rule argument

spec: int-abs inst: name: Abs-neg seq: ⊦ j < 0 → abs(j) = 0 - j subst: [j] → [i] flags: rewrite

Additional information

Used terms: i