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Proof step 25 from proof div-nearer-zero (previous step)

~(j * i / j) = ~ j * ~ i / ~ j, ~ i < ~(j * i / j), j + 1 < i / j, 0 < i / j, i < i / j, i + 1 < i / j, i < 0, j * i / j < i, j * i / j < ~1, j < 0, j < i / j ⊦ j = 0

User applied rule insert equation

And obtained the following new goals

Rule argument

pos: left 1 flags: discard

Additional information