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Proof step 1 from proof div-rec-01 (conclusion)

j < 0, i ≤ j ⊦ i / j = (i - j) / j + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i ≤ j, j < 0, i < 0 ⊦ i / j = (i - j) / j + 1

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs