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Proof step 5 from proof div-rec-01 (previous step)

1 = i / j + (j - i) / j, i ≤ j, j < 0, i < 0 ⊦ i / j = (i - j) / j + 1

User applied rule cut formula

And obtained the following new goals

Proof step 6:
i / j = 1 - (j - i) / j, 1 = i / j + (j - i) / j, i ≤ j, j < 0, i < 0 ⊦ i / j = (i - j) / j + 1

Rule argument

fma: i / j = 1 - (j - i) / j

Additional information

Used simplifier rules: sub-eq: ⊦ i - j = i0 ↔ i = i0 + j; from specification int-abs Used formulas: i / j = 1 - (j - i) / j