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Proof step 9 from proof div-rec (previous step)

j * (i1 + 1) + j0 = i0 * j + j1 ∧ 0 ≤ j1 ∧ j1 < j, j0 < j, 0 < j, 0 ≤ j0, 0 < j * (i1 + 1) + j0, 0 ≤ i1 ⊦ i0 = i1 + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs