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Proof step 14 from proof div-shift-two (previous step)

i0 * j + j0 < (1 + 2 * i0 / 2) * j, j0 < j, 0 < j, 0 ≤ j0, 0 ≤ i0 ⊦ i0 = 0 + 2 * i0 / 2, j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
i0 * j + j0 < (1 + 2 * i0 / 2) * j, j0 < j, 0 < j, 0 ≤ j0, 0 ≤ i0 ⊦ j = 0, i0 = 2 * i0 / 2

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-zero: ⊦ i + 0 = i; from specification int-basic2