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Proof step 4 from proof div-sub-01 (previous step)

j ≠ 0, ∃ j0. i = j0 * j, i0 % j = 0 ⊦ j = 0, i / j = (i - i0) / j + i0 / j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
i0 % j = 0 ⊦ j = 0, j0 = (j0 * j - i0) / j + i0 / j

Rule argument

Additional information

Used simplifier rules: div-mult-03: j ≠ 0 ⊦ (i * j) / j = i;%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult