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Proof step 1 from proof div-sub (conclusion)

j ≠ 0 ⊦ (j - i * j) / j = 1 - i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ j = 0, 1 = (j - i * j) / j + i

Rule argument

Additional information

Used simplifier rules: sub-eq: ⊦ i - j = i0 ↔ i = i0 + j; from specification int-abs