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Proof step 10 from proof div-two-intro (previous step)

⊦ 0 < 2 ∧ 0 ≤ i, i % 2 = 0, i / (j0 * 2) = (i / 2) / j0, j0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
i < 0 ⊦ i % 2 = 0, i / (j0 * 2) = (i / 2) / j0, j0 = 0

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs