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Proof step 15 from proof div-two-intro (previous step)

i0 * 2 = i1 + 1, i0 ≤ 0 ⊦ j0 = 0, i1 / (j0 * 2) = i0 / j0

User applied rule cut formula

And obtained the following new goals

Proof step 16:
i1 = i0 * 2 - 1, i0 * 2 = i1 + 1, i0 ≤ 0 ⊦ j0 = 0, i1 / (j0 * 2) = i0 / j0

Rule argument

fma: i1 = i0 * 2 - 1

Additional information

Used simplifier rules: sub-eq: ⊦ i - j = i0 ↔ i = i0 + j; from specification int-abs Used formulas: i1 = i0 * 2 - 1