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Proof step 17 from proof div-two-intro (previous step)

i0 ≤ 0 ⊦ j0 = 0, (i0 * 2 - 1) / (j0 * 2) = i0 / j0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 18:
i < 0, 0 < j ⊦ (2 * i - 1) / (2 * j) = i / j
Proof step 19:
¬(i0 < 0 ∧ 0 < j0), i0 ≤ 0 ⊦ j0 = 0, (i0 * 2 - 1) / (j0 * 2) = i0 / j0

Rule argument

spec: int-div inst: name: div-twoodd-03 seq: i < 0, 0 < j ⊦ (2 * i - 1) / (2 * j) = i / j subst: [j, i] → [j0, i0] flags: rewrite, current

Additional information

Used simplifier rules: commutativity: ⊦ i * j = j * i; from specification int-mult Used terms: j0, i0