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Proof step 23 from proof div-two-intro (previous step)

i0 ≤ 0 ⊦ j0 = 0, (i0 * 2 - 1) / (j0 * 2) = i0 / j0, i0 < 0 ∧ 0 < j0, i0 < 0 ∧ j0 < 0

User applied rule cut formula

And obtained the following new goals

Proof step 24:
i0 = 0, i0 ≤ 0 ⊦ j0 = 0, (i0 * 2 - 1) / (j0 * 2) = i0 / j0, i0 < 0 ∧ 0 < j0, i0 < 0 ∧ j0 < 0

Rule argument

fma: i0 = 0

Additional information

Used simplifier rules: lels-02: ⊦ i ≠ j → (i ≤ j ↔ i < j); from specification int-abs%zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs%lst-01: ⊦ ¬ i < j → (i ≠ j ↔ j < i); from specification int-basic1%ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1 Used formulas: i0 = 0