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Proof step 1 from proof div-two-zero (conclusion)

⊦ 0 < i → (i / 2 = 0 ↔ i = 1)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: div-eq-zero: ⊦ 0 < i ∧ 0 < j → (i / j = 0 ↔ i < j);%two-ls: ⊦ 0 < j → (j < 2 ↔ j = 1); from specification int-basic1