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Proof step 7 from proof div-twoodd-02 (previous step)

j * 2 < 0, 0 ≤ i, j < 0 ⊦ ~((2 * i + 1) / (~ j * 2)) = i / j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ i * j = j * i
Proof step 9:
j * 2 < 0, 0 ≤ i, j < 0 ⊦ ~((2 * i + 1) / (2 * ~ j)) = i / j

Rule argument

spec: int-mult inst: name: commutativity seq: ⊦ i * j = j * i subst: [j, i] → [2, ~ j] flags: rewrite

Additional information

Used terms: 2, ~ j