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Proof step 2 from proof div-twoodd-05 (
previous step
)
2 * i + 1 = 2 * (i + 1) - 1, i < 0, 0 < j ⊦ (2 * i + 1) / (2 * j) = (i + 1) / j
User applied rule insert equation
And obtained the following new goals
Proof step 3
:
i < 0, 0 < j ⊦ (2 * (i + 1) - 1) / (2 * j) = (i + 1) / j
Rule argument
pos: left 1 flags: discard
Additional information