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Proof step 1 from proof div-twoodd-06 (conclusion)

0 ≤ i, j ≠ 0 ⊦ (2 * i + 1) / (2 * j) = i / j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 ≤ i ⊦ (2 * i + 1) / (2 * j) = i / j, j = 0

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs